 
  
  
   
 Consider a pressure- less distribution of non- interacting particles [ called dust ], with rest mass m and number density n in the momentarily comoving reference frame [ MCRF ] .
  
 
In a general frame the number density will go up by a factor
  
 
  
 
and
  
 
so
  
 
Thus the density   is not a component of a four- vector.
We will see that it is a component of a 2/0 tensor.
  is not a component of a four- vector.
We will see that it is a component of a 2/0 tensor.
We can introduce a number flux  
four- vector   :
 :
  
 
where   is the flux per unit area across a 
surface with normals in the x direction etc, and
  is the flux per unit area across a 
surface with normals in the x direction etc, and   can be interpreted  as the flux across a constant ct surface.
Thus
 
can be interpreted  as the flux across a constant ct surface.
Thus   combines the flux and the number density in a 
single four- dimensional quantity. Note that
  combines the flux and the number density in a 
single four- dimensional quantity. Note that 
  
 
The most convenient definition of the energy- momentum tensor is in terms of its components in some arbitrary frame.
  
 
where   is the flux of
  is the flux of   - momentum
across a surface of constant
 - momentum
across a surface of constant   . By
 . By   -
momentum we mean the
 -
momentum we mean the   component of the four- momentum
  component of the four- momentum
  .
  .
Let us see how this definition fits in with the discussion 
above. Consider first   . This is defined as the flux
of 0- momentum [ energy divided by c ] across a surface
of constant t. This is just the
energy density .
 . This is defined as the flux
of 0- momentum [ energy divided by c ] across a surface
of constant t. This is just the
energy density . 
  
 
Similarly,   is the flux of energy divided by c
across a surface of constant
  is the flux of energy divided by c
across a surface of constant   :
 :
  
 
Then   is the flux of i- momentum across a surface of
constant t: the density of i- momentum multiplied 
by c:
  is the flux of i- momentum across a surface of
constant t: the density of i- momentum multiplied 
by c: 
  
 
Finally   is the j- flux of i- 
momentum:
  is the j- flux of i- 
momentum: 
  
 
For any particular system, giving the components of   in
some frame, defines it completely.
  in
some frame, defines it completely.
For dust , the components of T in the MCRF are particularly simple. There is no motion of the particles, so all i- momenta are zero and all spatial fluxes are zero. Therefore:
  
 
It is easy to see that the tensor   has exactly these
components in the MCRF, where
  has exactly these
components in the MCRF, where   is the four- momentum
of a particle. It follows that, for dust we have
  is the four- momentum
of a particle. It follows that, for dust we have
  
 
From this we conclude that the components of   are:
  are:
  
 
or in matrix form:
  
 
In a frame   with
  with   , we therefore have
 , we therefore have 
  
 
These are exactly what we would calculate from first principles, for the 
energy density , energy flux , 
momentum density  and momentum flux  respectively.
Notice one important property of   : it is 
symmetric:
 : it is 
symmetric: 
  
 
This will turn out to be true in general, not just for dust.
 
 
  
  
  